0 Members and 3 Guests are viewing this topic. Read 541130 times.
Hang in there Matt, I ordered mine on the 4th and got it yesterday. Works great, no noise or hums. The only problem was a volume set screw was loose on the inside, just a good excuse to take the cover off. Just one night of use and I know it's well worth the price. Not huge differences with my purist, but the purist isn't an ordinary passive either. It's kind of funny, every difference I noticed had a positive and a negative side. The TVC has more bass, but it is a little less tight, more detail and impact, but with a slight harshness, A tighter image but not as wide or deep. Granted, the TVC is right out of the box, the differences are slight, and I didn't do any level matching or anything. After I enjoy it for a couple weeks, I'll do more serious comparisons. I've allways bought used so I've never heard break-in, It's very good now, any improvement would be sweet.Ryan
I wish I wouldn't have posted yesterday, I was just excited about getting a new toy. Listening to a brand new component for one night isn't a good basis for making judgments. I've had the purist for several years and am very accustomed to it's sound, so anything with more detail and impact might sound a bit harsh to me. I'm enjoying the TVC very much, and after a few weeks I should be able to make a better comparison.Ryan
GHM, i just peeped your system..holy cow. I'm really interested in the Brines FTA-2000's. Do they really playlow bass? I'm not the type to get a sub, I like full range floorstanders.at some point I will replace my Thiels & am leaning towards a single driver designbut I haven't heard any that play the way i like. haven't heard too many though..
You got me lost on the Energizer now. So this thing just plugs in the wall? Does it need to be plugged near the same outlet as the other equipment? I'm thinking it does.Never heard of anything like that before.
So, during the positive-half of the power cycle, energy is transferred by the source to the inductor and stored in its magnetic field. During the negative-half of the power cycle, the energy stored in the inductor is transferred back to the source.When the inductor is returning energy to the source I suppose that the amplifier connected to the same source could make use of that energy. (I not exactly sure by what "using the energy means")But what if the music calls for more energy when the inductor is actually absorbing it? Under AC conditions, there is no reservoir of energy from to call upon.
I would like to emphasize that my post is no way being combative or dismissive of the product. Just trying to understand.
Yes, though we need to back up here a little bit and consider the energy stored in the inductor in the first place. That's ultimately determined by the current flowing through the inductor in the form of 0.5LI2. So if we have say a 10 Henry inductor, its reactance will be 2 x pi x f x L. At 60 Hz, that comes to 3,770 ohms. With 120 volts across the inductor, peak current will be 120/3,770 or about 32 milliamps.That means that the peak energy stored by the inductor will be 0.5 x 10 x 0.001 or just 5 millijoules (0.005 Joules).As I said originally, there's hardly any energy being stored at all.
Also, most every power supply out there is of the capacitor input type. These only draw current from the AC line for a brief period of time at the peak of the AC voltage waveform. If we're talking about pure inductance, the phase angle of the current will be 90 degrees relative to voltage. So at the point when the power supply is drawing current from the AC line, the current in the inductor, and therefore the energy stored in it, is effectively zero.
5 mJ need not necessarily be a small amount of energy. It is equivalent to 3.12 x 1016electron-volts. If I understand correctly, the effect of that energy depends on the number of particles (electrons) that absorbed that energy.
This one took a while for me to figure out. I assume the capacitor input you are talking about is the first capacitor after the rectifier. A quick simulation in PSUD helped in understanding.
With the voltage of the AC line leading the inductor current by 90 degrees, it is true that when the voltage peaks (at 0, pi, 2pi etc. for example), the instantaneous value of the inductor current is zero, and hence instantaneous energy stored in the inductor is zero. However, the energy function is at the end of its downward movement, and the inductor has finished transferring whatever energy it had stored over the upward half-cycle back to the source. And this energy is available when the power supply demands current from the source (at the peak of the source voltage). What does having this energy reserve mean? That the AC source can meet the current demand without a voltage dip? But the ac source is the electric supply from the utility company. And the demand of an amplifier should hardly cause a dip in the voltage (after inrush effects have disappeared).