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Not trying to thread jack but maybe someone can help me out without starting a new thread. I'm also in the midst of building a new house with a dedicated listening room/home theater. For my front three speakers I use 3 GR Research LS9s. Yes huge speakers therefore I need a large room. I'm looking at a minimum of 20x30 feet. With the 3x5x8 ratio mentioned that would make for a very high ceiling which I'm not sure is feasible. Any suggestions for dimensions for a room with these speakers would be greatly appreciated!!
If the 3m x 5m x 8m is too big, I would try this room JLM mention (2,8m x 4,1 x 6,7m or even 2,8 x 4,2m x 6,7m) seem perfect to a dedicated music room, with few forniture of course;
I recall the "golden" ratio as being .61 to 1 to 1.61 (.61 being the lowest number of the 3D rectangle) which is ceiling height. That height in most homes is 8'. That means the next number is 13', and the next number is 21'. That simply implies that the room has non-participating boundaries that would induce standing waves. You can also set the speakers along the long wall with equally wonderful results.Personally, I think Mr. Cardas simply stole his idea of his own unique golden rule and morphed it a bit to suit himself, but these rations are from biblical times. I believe many churches were built to these ratios, and we all know that many are very "mystical" in their natural reverberations and even power dynamics. Add a nice pipe organ and your in business......Just my 2 cents.Wayner
2.4 ceiling with 8 length breaks one of the rules of never having length or width be >= 3x the height.Bryan
my suggestion is isolate the shit out of it, plan on absorbtion and diffusion and bigger is better.
That is a good plan, but it's nice (if you have the option or opportunity) to take advantage of the basic math for the room. Perhaps less treatment would be needed.I also believe that room symmetry is critical. That includes positions of windows, doors, etc.Wayner
I was never good at math and not sure how to translate the mentioned golden rule and other room calculations into room sizes so any help on this is greatly appreciated. If the room is 34" 8' x 18" 7' what height would be ideal? Are there any problems with that depth/width of the room? Also the room will be heavily treated. In my current room I have 4 tri traps, 10 244's, and 14 224's. my plan is to add some diffusion in the new room however.
Not trying to thread jack but maybe someone can help me out without starting a new thread.
I would be careful with too many 242's. Use the Tri and 244's primarily and add the 242's as required. As for the height, the with a 34' 8" length, the room would have to be at least 11'8". That's not any specific ratio - just tall enough to not break the 3x rule.Bryan