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I actually know what the last four of those mean, but I am still pretty much intimidated out of doing this.
I don't think this question has been answered yet. A crossover is not a "brick wall" filter - it has a gradual transition, which occurs on the "pass" side as well as the "stop" side of the nominal crossover freqency. For example, here is the frequency response of a first-order filter:Here is a steep filter - you can see the transition is much sharper but it's still there:If you leave the passive crossover in, your active crossover can only "add" to this kind of response i.e. make the slopes steeper. If your crossover frequency was not the same as in the passive crossover, then you would also have to boost one output near the crossover frequency to try and counter its effect. That would be problematic. With the same crossover frequency, I think it probably is doable but you would need to be aware that the response you get from each driver includes the response caused by the passive crossover. If you are OK with using steeper slopes (and I see nothing wrong with that) and are using a digital crossover (with choice of lots of different slopes), you might be able to get it to work well. However, it would still most likely be "better" to remove the passive crossover. At the least, it might be worth a try just to get started and see how it goes, use it as a way to learn about how to set up an active crossover, before deciding to remove the wiring from the drivers. At that point you might also decide to go full 3/4 way. You may decide that rather than destroy the resale value of the speaker you would rather go active with something DIY. That is all assuming that you can measure as mentioned by others.
Also, there is (at least) one other thing I am unclear on. Does the low (in my case 150 Hz) crossover span just the lower pair of binding posts and the woofer, or does it also connect to the mid-range. In other words, in my current passive bi-amp configuration, does the lower-frequency crossover work only on the "bottom" channel to remove the higher-frequency signals, or does it only work on the "top" channel to remove the lower-frequency signals, or are there two, or what?
Thanks for this. Mind if I ask some "Devil's advocate"-type questions?If the crossover frequencies did match, presumably the net slope you would get would be whichever is steeper to begin with, though. I'm not sure they are additive (and as you point out, it would just make it a bit more steep). If the active crossover had a more shallow slope, I could see how this might be problematic.
Also, why is having a resistor in a passive crossover worse than having a (variable potentiometer) resistor further upstream in the amp to reduce gain?
No - they are additive (magnitude in dB terms, phase in radians/degrees). Crossover are just filters, and that's how filters work... sorry, I'm at a bit of a loss how to explain it off the cuff (and without getting into theory)...
If you left the midrange and tweeter connected through their internal passive crossovers to the upper pair of binding posts as they currently are, you would be both actively and passively filtering the 350Hz crossover point - probably not a good idea.
The CM7 crossover frequencies are 350Hz and 4000Hz. There are three crossover circuits employed. The woofer receives frequencies up to 350Hz, the midrange 350Hz to 4000Hz and the tweeter 4000Hz and up. To my knowledge, the lower pair of binding posts feeds the woofer crossover only, and the top pair feeds both the midrange and tweeter crossovers.
Thanks.That is what I was afraid of.