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Hi Folks,Wonder IF the traditional Mu Follower Circuit is best suited for Preamps, Power amps input stage or both??What do you think??Gustavo
Decreasing the ratio from 100:1 to 10:1 results in virtually no increase in harmonic distorion. As a general example, if the total harmonic distortion at 2v rms output measures .01% (-80db) using the 100:1 ratio, changing to 10:1 raises the distortion by approximately .012% to -79db, a rise of approx 1db. It could be more depending upon the loadline and tube distortion in general.Let's check for any high frequency response advantages vs preamplifier output impedance (Z). If one uses a high capacitance interconnect cable (IC) and include amplifier input capacitance, say 250pf of total capacitance, and the output impedance (of the preamplifier) rises from 100 ohms to 2000 ohms, the high frequency response drops approx 0,4db at 100,000 cycles per second, and approximately .015db at 20khz. Using a 50pf interconnect cable results in less than 0,02db drop at 100khz, and virtually zero at 20khz. By the way, everyone knows that capacitances should be minimized with interconnect cables. (However, rarely, a longer IC with higher capacitance is neccessary as there is no choice.) Actually a major portion of the loss in high frequency response is due to the volume control resistance/input tube capacitance relationship.
Hi Gustavo,It depends upon some factors such as output impedance of the preamplifier, miller capacitance of the input stage etc. From my white paper here are some figures concerning distortion and high frequency response. (100:1 to 10:1 refers to the input impedance (Z) of the amplifier divided by the preamplifier output Z, using separates. General conditions as some high distortion tubes may have greater distortion than indicated.)If the capacitance is, say 125pf total, the FR will drop off only approximately 0.0075db at 20khz. However, a mu follower type etc does add another stage, with all the associated parts, which will degrade the musical signal further.Hope this helps. Cheers.
Thanks Boys for the input, very illuminator.IF I get the idea, this tube circuit depends on the tubes impedances to work properly.Excuse my ignorance again, I understand what it capacitance, but what is Miller Capacitance in tubes??Gustavo
Thanks Steve for this detailed explanation.Looks Miller is the inner capacitance between the tube elements, and with others parts and tubes.Best Wishes, Gustavo
Oh, very clear now , Thanks for this lesson Steve, you are a good teacher!! Congratulations.Thanks again, Gustavo