With a resistor in place, adding resistance in parallel will actually lower the sum resistance. Here's the formula:
Resistance (total) = 1/[(1/R1)+(1/R2)+(etc.)], where R1 and R2 are the values of the two respective resistors.
Since you are only dealing with two resistors, you could use the product-over-sum formula: R(total) = (R1*R2)/(R1+R2)
If the two resistors were equal values, the R(total) would simply be half that value, or R/2.
You might scratch your head and say to yourself, 'wouldn't it just be easier to replace the 47K with a 62K resistor than to deal with all that math?'
And you would be right.