For voltage, if the linear gain is X, then
dB = 20 log X
(Where the log is base 10.)
Conversely going the other way
X = 10 ^ (dB/20)
Also, linear gain multiplies, and dB adds. A quick to do it is to remember that a linear gain of 2 equals 6dB and a linear gain of 10 equals 20dB. Then you cheat by converting everything into multiples of 2 and 10.
So if you meant that the linear gain of the stages is 16 and 3.5, then 16 = 2x2x2x2 = 6+6+6+6dB = 24dB. A gain of 3.5 is a bit less than 2x2 = 6+6dB = 12dB, say 11dB. So the total (open loop, I presume) gain of the amp is 35dB. Feedback will lower that of course.
Input sensitivity is stated with respect to full power output... you would have to provide more information.