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Anyway, when I get a chance I'll take your example above (which was perfect, thanks), replace my equivalent circuit with a long series of LC elements, and see if I believe you.
So why not just go back to Radio Shack and buy some 25 cents per foot 14 gauge standard low capacitance speaker wire? The object is the music, the best music possible for the money.Frank Van Alstine
Lithium phosphide + sodium phosphide ... that could do the trick. You just make the conductor if indium + gold... then you make the sheath of Cyclic carbonate-modified siloxane that can retain a charge and be shaped in many ways, and even recharged or, you know..Now the indium + gold is actually a magnetic alloy, so it will have a field..When you play with the cable it will charge its dielectric sheath... You make lots and lots of very small transformers and chain them up!!! That's your conductor...Eh? Imperial
Right, never mind. I'll keep the chemistry out of cable debates.. The stuff anyway will conduct a charge, let's just say that. There are a lot of names and obviously I shouldn't play havoc here with chemistry.. It's just ... you talked about signal traveling faster than light, so I thought you were making a joke...I just wrote a joke too.. (Lithium phosphide + sodium phosphide is a drug against delusional states in the brain..)But obviously you did not joke? Signal faster than light? Is that possible?Imperial
Hehe.. you give lithium to people who hears voices...You wrote some posts above that the voices had stopped talking.. aaOk. We can't know it all, can we.. I guess I should speak more accurate, and not try a funny side 'trip'Sorry jneutron, I'm a evil 'git sometimes.. Imperial
Here's a good example:
If one were to be rigorous in the application of lumped elements, the line has to be modelled as a long string of LC's.. Otherwise, the models fall apart when the load matches the line.
SThis all kind of sounds like "how to make my Rolex keep exact time." The answer of course is buy a Timex.Not that I am knocking Rolexes, I have one, its jewelery, my only piece of jewelery, but I don't confuse it with WWV time. Now I am going to hear bad things from those who "know" that Rolexes aren't really the best of jewelery. I don't care. Best regards,Frank Van Alstine
Now, let's compare that to the equivalent circuit (where the voltage source is connected across the capacitor of a standard series RLC circuit). When I work that out I find an expression for Z which I don't want to type here because it would be hard to read, but it has the property that it agrees almost perfectly with the results of the exact solution so long as omega^2*l^2*L*C is small, where omega is the driving frequency and l is the length of the cable. But if we take your numbers from above, that just means the cable should be less than a few kilometers long (just as I said originally). And moreover the impedance has precisely the characteristics Daryl said (which is why it made sense to me in the first place).So to summarize: for analogue audio signals traveling down speaker cables less than kilometers in length one can use a plain old RLC equivalent circuit. Transmission line theory, while technically more precise, is unnecessary and total overkill.
Was your analysis based on the assumption that the load impedance matches the characteristic impedance of the line?
That is almost never true in audio (except for S/PDIF which could technically be considered RF). In order to show that simple two-element lumped circuit analysis is sufficient for any load impedance, that's a more complex problem.
OK, I had a chance to sit down and work this out. First off, you're right that when the load impedance matches the line impedance, the amp just sees the load. But that follows also from the simple equivalent circuit analysis (which I hadn't noticed before), and in general I was correct that one can always use the equivalent circuit for audio frequency signals in speaker cables.
So to summarize: for analogue audio signals traveling down speaker cables less than kilometers in length one can use a plain old RLC equivalent circuit. Transmission line theory, while technically more precise, is unnecessary and total overkill. And this claim:Quote from: jneutronIf one were to be rigorous in the application of lumped elements, the line has to be modelled as a long string of LC's.. Otherwise, the models fall apart when the load matches the line.is wrong. The equivalent circuit model works fine in that case so long as the frequencies in question are sub-RF.
Nice.An RLC model runs flat from DC to daylight? How did you model that?
I see you are also running into the chicken and the egg problem..which is first, the C or the L...
Model the settling time by varying the line to load ratio. It must produce a cusp minima at unity....zero if you offset the transit time.
I have an exact equation (in the limit we can ignore the resistance of the cable) which follows directly from the telegrapher's equations plus the correct boundary conditions for the load and source. That equation can be Taylor expanded in the limit that omega^2 LC is small. It's slightly tricky in that you have to expand past first order, but it looks like the result agrees with the simple circuit to the same order. The corrections are of order omega^2 LC, which is tiny for speaker cables.