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Okay, the question of 95 ohms aside, what happens to the power output at 16 Ω and 32 Ω?
To over-simplify. E = sq.rt. P*RSo if the amp is voltage limited. 2 Ohm 400W = 28.3V 4 Ohm 200W = 28.3V 8 Ohm 100W = 28.3V16 Ohm 50W = 28.3V32 Ohm 25W = 28.3V95 Ohm 8.4W = 28.3V
Voltage is preserved. The other important factor to understand is how the impedance changes with frequency and also how the sensitivity changes with frequency. With that information you can predict the max spl available at 1m since you know what the power output is at that particular frequency.
Voltage is preserved meaning?So even though a given amplifier may be capable of 400 watts at a low impedance, it may put out as little as 8 watts at a higher impedance. If this is so, then there is a lot to matching an amp (in terms of power) to a given pair of speakers than most might be inclined to think?
But the speaker curve in reply #2 is a different story. The impedance spike is at the bass-reflex tuned frequency, the loudspeaker's efficiency goes way up at that frequency so it needs hardly any power.
P = V(squared)/impedance.
Very few SS amps can work in 2Ω
even fewer can work in 16Ω I unknow any capable. Watts in SS amps at 16Ω are not informed why they cant operate in this hi resistance.
It is worth noting that most of what has been discussed here applies to voltage amps. Current amps increase power as impedance increases........................................ .....................dave
Hi-fi current amplifiers are only slightly more common than unicorns.
I thought most SS amps were current whereas tube amps were voltage?