Karma: Wilco "Yankee Hotel Foxtrot," "Being There" and "A.M." CDs

krikor · « **on:** 20 Jan 2014, 07:37 pm »

This karma offering is for both CDs in flatpak envelopes (they were included with the vinyl albums I recently bought, but I already have the discs). Pick a number from 11 to 66 and I'll randomly select winner using a pair of dice (one for each digit). Person with the closest number gets the CDs.

~~(Sorry for upside down image... never seems to work using my iPad)~~ FIXED!

BONUS!! I forgot that I also have a CD flatpak of Wilco's "A.M." which will be provided to the winner as well!

rockadanny · « **Reply #1 on:** 20 Jan 2014, 08:13 pm »

dburna · « **Reply #2 on:** 20 Jan 2014, 08:18 pm »

Mike Nomad · « **Reply #3 on:** 20 Jan 2014, 08:22 pm »

Charles Xavier · « **Reply #4 on:** 20 Jan 2014, 08:53 pm »

36 thanks

WC · « **Reply #5 on:** 20 Jan 2014, 08:56 pm »

bplexico · « **Reply #6 on:** 20 Jan 2014, 10:54 pm »

55. Thank you regardless of who wins!

SlushPuppy · « **Reply #7 on:** 20 Jan 2014, 11:51 pm »

I already have them, but I think you're cool for doing this

bladesmith · « **Reply #8 on:** 20 Jan 2014, 11:54 pm »

Peter J · « **Reply #9 on:** 21 Jan 2014, 12:06 am »

Cool! I'll give sweet 16 a whirl!

thunderbrick · « **Reply #10 on:** 21 Jan 2014, 12:28 am »

rif · « **Reply #11 on:** 21 Jan 2014, 01:42 am »

Ern Dog · « **Reply #12 on:** 21 Jan 2014, 03:58 am »

Cool karma, thanks!

I'm in with 21.

decal · « **Reply #13 on:** 21 Jan 2014, 12:38 pm »

Count me in with 57, thanks.

Ericus Rex · « **Reply #14 on:** 21 Jan 2014, 05:13 pm »

12

Scotlynn · « **Reply #15 on:** 21 Jan 2014, 05:21 pm »

Very generous. I'll pick lucky number 13!

bummrush · « **Reply #16 on:** 21 Jan 2014, 05:34 pm »

bummrush · « **Reply #17 on:** 21 Jan 2014, 05:35 pm »

15. Since 12 is gone

krikor · « **Reply #18 on:** 21 Jan 2014, 08:53 pm »

BONUS!! I forgot that I also have a CD flatpak of Wilco's "A.M." which will be provided to the winner as well!

krikor · « **Reply #19 on:** 23 Jan 2014, 08:25 pm »

Just to clarify... I'm using a pair of dice to determine the winner, with one die representing each digit in the number. Sooo... it is not possible for me to land on any numbers with a 7, 8, 9 or 0.

If you would like to change your number, please modify your post after checking that the new number has not been selected already.

Of course, I'm going to pick the person that is closest to whatever number I roll with the die, so you still may win with one of those numbers.