Sam,
The higher the shunt resistor used, then the less the signal strength to the tube, in fact the relationship is Rv/(Rv + Rs). Thus signal loss from input to output with 27K shunt and 10K DACT is 10/37, which is 27%, or -11.4dB. A lot. If you reduce the shunt resistor to maybe 10K, then signal loss is 0.5, or 50%, or -6dB, a lot less.
This would be my choice, in fact.
Cheers,
Hugh