Please explain how current is reduced. If one speaker is wired out of phase without changing the internal wiring I would think both speakers get the same current. All that happens is the bass cancels so you can play them louder without disturbing the neighbors. Place the speakers face to face with a couple of inches between and throw some blankets on top to muffle the sound.
Placing the speakers face to face in opposite polarity makes one pull while the other pushes. The pressure of the air between them does not change much. There is less energy draw to create air pressure impulse. This is why it's quieter. They each help the other move their cones. One rarifies the air while other pressurizes. The combined power is halved or less. The mechanical aspects will break in but the conductor insulation and caps will go slower.
The speakers are not doing their job of pressurizing air to create impulse. No matter how high you turn it up the other speaker is still helping by the increased amount. The pressure between them remains too low. Yes some leaks out but most is cancelled.
In a reflex speaker playing signals with frequencies lower than port resonance at these artificially raised voltage levels can do mechanical damage to woofer if it is overextended due to driving very low air pressure.
Unassisted speakers working in free air as designed will work harder to move the air and draw more current at same voltage signal.
My philosophy on break in is, I'm not a reviewer, I'm not in a hurry to finish by a deadline. I don't juggle gear so I will have this for a while. I can afford to wait and enjoy noticing how it improves. I just play music and let it come into its own in its own time. I do however take the opportunity to catch up on Rush, Kenton and Russian symphonies with new speakers.
